The function is
.
All possible values of
is the domain of the function.
Since it is a rational function, the denominator of the function should not be the zero.
\


and 
and 
Therefore, the domain of the function is all real numbers of
except
and
.
Domain in set-builder notation is
.
The domain in interval notation is
.
Ana thinks the domain is
.
Mason thinks the domain is
.
So Ana is wrong.
\Mason answer is correct.
\ \Mason answer is correct.