The division is
.
Rewrite the given expression, so that the divisor is in the form of
.

Dividend is
.
Divisor is
.
The divisor obtained is
.
Now the divisor is in the form of
.

Where
.
Setup the synthetic division using a zero place for the missing term
term in the dividend.

Write the constant
of the divisor
to the left.
In this case,
.
Bring the first coefficient,
down.
Multiply the sum,
by
:
.
Write the product under the next coefficient,
and add :
.
Multiply the sum,
by
:
.
Write the product under the next coefficient,
and add :
.
Multiply the sum,
by
:
.
\
Write the product under the next coefficient,
and add :
.
Multiply the sum,
by
:
.
\
Write the product under the next coefficient,
and add :
.
Multiply the sum,
by
:
.
\
Write the product under the next coefficient,
and add :
.
The remainder is the last entry in the last row.
\\
Therefore, the remainder
.
The number along the bottom row are the coefficients of the quotient.
\\
Start with the power of x that is one less than the degree of the dividend.
\The remainder
can be written as
.
So the quotient is
.
.