The function is
and the value of
.
Setup the synthetic division using a zero place for the missing terms
in the dividend.
Perform synthetic substitution method to evaluate
for
.
Since the remainder is
,
.
Check the function at
at
using direct substitution method.
The result is verified.
\The remainder of
at
is
.
Since the remainder is non zero,
is not a solution of the given equation.