$\"\"$

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The function is $\"\"$ .

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The factors are $\"\"$ and $\"\"$ .

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Perform the synthetic division method to test each factor.

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Synthetic division for factor $\"\"$ .

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The divisor is in the form of $\"\"$ .

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$\"\"$

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$\"\"$

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When $\"\"$ is divided by $\"\"$ The remainder is $\"\"$ .

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So $\"\"$ is not a factor of $\"\"$ .

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$\"\"$

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Now test the second factor $\"\"$ ,for the polynomial $\"\"$ .

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Synthetic division for factor $\"\"$ .

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The divisor is in the form of $\"\"$ .

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$\"\"$

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$\"\"$

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When $\"\"$ is divided by $\"\"$ The remainder is $\"\"$ .

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So $\"\"$ is not a factor of $\"\"$ .

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$\"\"$

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Both the factors $\"\"$ and $\"\"$ do not obtain the remainder $\"\"$ .

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So $\"\"$ and $\"\"$ are not the factors of $\"\"$ .