The function is .

The factors are and .

Perform the synthetic division method to test each factor.

Synthetic division for factor .

Rewrite the division expression so that the divisor is in the form of .

Setup the synthetic division using a zero place for the missing terms in the dividend.

.

The divisor obtained is .

Now the divisor is in the form of .

When is divided by  , the remainder is  .

So is not a factor of .

Now test the second factor ,for the polynomial .

Synthetic division for factor .

The divisor is in the form of

When is divided by  , the remainder is  .

So is not a factor of .

Both the factors and do not obtain remainder .

So and are not the factors of .