(a).
\Identify Possible Rational Zeros :
\\
Usually it is not practical to test all possible zeros of a polynomial function using only synthetic substitution. The Rational Zero Theorem can be used for finding the some possible zeros to test.
\ The function is
.
Because the leading coefficient is
, the possible rational zeros are the intezer factors of the constant term
.
Therefore the possible rational zeros of
are
.
Examine the variations in sign for
and
:
Consider
.
The original polynomial equation has
variations in sign.
\
.
.
has
variations in sign.
Therefore by Descartes
rule of signs
has either
or
positive real zeros and
or
negative real zeros.
Synthetic Division :
\\
Consider
.
Perform the synthetic division method by testing
and
.
Since
, conclude that
is a zero of
.
Therefore,
is a rational zero.
The depressed polynomial is
.
Consider
.
Perform the synthetic substitution division on the depressed polynomial by testing
and
.

Since
, conclude that
is a zero of
.
Therefore,
is a rational zero.
Therefore,
and
are the factors of
.
The remaining factor is
.
The remaining quadratic factor
yeilds no real zeros and is therefore irreducible over the reals.
So
is written as a product of linear and irreducable quadratic factors is
.
(b).
\We can factor
by writing the expression first as a difference of squares
or
. Then factor the differences of squares as
.
So,
written as a product of linear factor as follows
.
(c).
\Because the function has degree
, by the corollary of the fundemental therom of algebra
has excatly
zeros,including any that may be repeated.
The linear factorization yeilds
zeros:
.
(a).
\
is written as a product of linear and irreducable quadratic factors is
.
(b).
\
written as a product of linear factor as follows
.
(c).
\The zeros are
.