The expression is
.
The expression is to be defined only when
.
Let
.
The above expression is in the form of
.
.
.
Therefore the factored form of
is
.
The real zeros of
are

Therefore
has
real zeros at
and
.
Create a sign chart using the values
and
.

Note : The solid circle denote that the value are included in the solution set.
\Determine whether
is positive or negative on the test intervals.
Test intervals are
and
.
If
then
.
If
then 
If
then
.
The solutions of
are
values for which
is positive or equal to
.
The solution set is
.
Therefore the domain is
.
The domain is
.