$\"\"$

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The inequality is $\"\"$ .

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The radical $\"\"$ is defined for $\"\"$ .

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The radical $\"\"$ is defined for $\"\"$ .

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Consider $\"\"$ .

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$\"\"$

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Consider $\"\"$ .

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$\"\"$

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The domain of the equation is restricted to $\"\"$ .

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$\"\"$

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Now consider the original inequality equation $\"\"$ .

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Squaring on both sides.

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$\"\"$

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$\"\"$

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$\"\"$ .

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Now squaring on both sides.

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$\"\"$ .

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$\"\"$

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$\"\"$

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Consider $\"\"$ .

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$\"\"$ .

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$\"\"$

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Let $\"\"$ .

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$\"\"$

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Therefore $\"\"$ has real zeros at $\"\"$ and $\"\"$ .

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$\"\"$

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Create a sign chart using the values $\"\"$ and $\"\"$ .

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$\"\"$

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Note : The hallow circle denote that the value are included in the solution set.

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Observe the sign chart :

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The set of value of $\"\"$ denoted in blue color represents the solution set.

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Determine whether $\"\"$ is positive or negative on the test intervals.

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Test intervals are $\"\"$ and $\"\"$ .

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If $\"\"$ then $\"\"$ .

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If $\"\"$ then $\"\"$ .

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If $\"\"$ then $\"\"$ .

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The solutions of $\"\"$ are $\"\"$ values for which $\"\"$ is positive or equal to $\"\"$ .

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The solution set is $\"\"$ .

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$\"\"$

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The domain of the equation is restricted to $\"\"$ .

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Create a sign chart that includes this restriction.

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When solving inequalities that involve raising each side to a power to eliminate a radical, it is important to test every interval using the original inequality.

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Substitute a $\"\"$ value in each test interval into the original inequality to determine if $\"\"$ is a solution.

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The original inequality equation is $\"\"$ .

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$\"\"$

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If $\"\"$ then $\"\"$ .

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If $\"\"$ then $\"\"$ .

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If $\"\"$ then $\"\"$ .

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If $\"\"$ then $\"\"$ .

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Therefore the solution set is $\"\"$ .

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$\"\"$

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The Solution set of $\"\"$ is $\"\"$ .