The inequality is
.
The radical
is defined for
.
The radical
is defined for
.
Consider
.

Consider
.
.
The domain of the equation is restricted to
.
Now consider the original inequality equation
.
Squaring on both sides.
\
Make sure to completely isolate the radical before squaring both sides of the inequality. Note change in sign.
\
.
Now squaring on both sides.
\
.
.
.
.
.
Consider
.
The above equation is in the form of
.
Where
.
The quadratic formula is
.
Now subustiute the values of
in the above equation.

Therefore
has
real zeros at
and
.
Create a sign chart using the values
and
.
Note : The solid circle denote that the value are included in the solution set.
\Observe the sign chart :
\The set of value of
denoted in pink color represents the solution set.
Determine whether
is positive or negative on the test intervals.
Test intervals are
and
.
If
then
.
If
then
.
If
then
.
The solutions of
are
values for which
is negitive or equal to
.
The solution set is
.
The domain of the equation is restricted to
.
Create a sign chart that includes this restriction.
\When solving inequalities that involve raising each side to a power to eliminate a radical, it is important to test every interval using the original inequality.
\Substitute a
value in each test interval into the original inequality to determine if
is a solution.
The original inequality equation is
.
If
then
.
If
then
.
If
then
.
If
then
.
Therefore the solution set is
.
The Solution set of
is
.