The inequality is
.
The inequality can be written as
.
Identify Possible Rational Zero:
\Usually it is not practical to test all possible zeros of a polynomial function
\using only synthetic substitution.
\The Rational Zero Theorem can be used for finding the some possible zeros to test.
\The function is
.

Because the leading coefficient is
, the possible rational zeros are the
integer factors of the constant term
.
or
Therefore, the possible rational zeros of
are

.
Perform the synthetic division method by testing
.

Since
, conclude that
is a zero of
.
Therefore
is a rational zero.
The remaining quadratic factor is
can be written as
.
The factored form of
is
.
Therefore the zeros are
and
.
Create a sign chart using the values
and
.
Note: The hallow circle denote that the value are included in the solution set.
\Observe the sign chart:
\The set of value of
denoted in blue color represents the solution set.
Determine whether
is positive or negative on the test intervals.
Test intervals are
and
.
Subustiute the values in the equation
.
If
then
.
If
then
.
If
then
.
If
then
.
If
then
.
The solutions of
are
values for which
is negative.
The solution set is
.
The solution set of
is
.