$\"\"$

\

The inequality is $\"\"$ .

\

The inequality can be written as $\"\"$ .

\

By trail and error method preform the synthetic division by testing $\"\"$ .

\

$\"\"$

\

Since $\"\"$ , conclude that $\"\"$ is a zero of $\"\"$ .

\

Therefore $\"\"$ is a rational zero.

\

The depressed polynomial is $\"\"$ .

\

$\"\"$

\

$\"\"$ .

\

By trail and error method preform the synthetic division on the depressed polynomial by testing $\"\"$ .

\

$\"\"$

\

Since $\"\"$ , conclude that $\"\"$ is a zero of $\"\"$ .

\

Therefore $\"\"$ is a rational zero.

\

The new depressed polynomial is $\"\"$ .

\

$\"\"$

\

$\"\"$ .

\

By trail and error method preform the synthetic division on the new depressed polynomial by testing $\"\"$ .

\

$\"\"$

\

Since $\"\"$ , conclude that $\"\"$ is a zero of $\"\"$ .

\

Therefore $\"\"$ is a rational zero.

\

The remaining quadratic factor is $\"\"$ can be written as $\"\"$ .

\

The factored form of $\"\"$ is $\"\"$ .

\

Therefore the zeros are $\"\"$ and $\"\"$ .

\

$\"\"$

\

Create a sign chart using the values $\"\"$ and $\"\"$ .

\

$\"\"$

\

Note : The solid circle denote that the value are included in the solution set.

\

Observe the sign chart :

\

The set of value of $\"\"$ denoted in blue color represents the solution set.

\

Determine whether $\"\"$ is positive or negative on the test intervals.

\

Test intervals are $\"\"$ and $\"\"$ .

\

Subustiute the values in the equation $\"\"$ .

\

If $\"\"$ then $\"\"$ .

\

If $\"\"$ then $\"\"$ .

\

If $\"\"$ then $\"\"$ .

\

If $\"\"$ then $\"\"$ .

\

If $\"\"$ then $\"\"$ .

\

If $\"\"$ then $\"\"$ .

\

The solutions of $\"\"$ are $\"\"$ values for which $\"\"$ is negitive or equal to $\"\"$ .

\

The solution set is $\"\"$ .

\

$\"\"$

\

The solution set of $\"\"$ is $\"\"$ .