The inequality is
.
is non negative.
Consider
.

Since
.
.
Let
.
is positive for all values of
.
Consider
.
The zeros of
are at
and
.
The zeros of
are at
and
.
Draw a sign chart by using the values
and
.
Note : The hallow circle denote that the value are excluded in the solution set.
\Observe the sign chart :
\The set of value of
denoted in blue color represents the solution set.
The zero at
is the location of sign change because it has multiplicity
.
\
The zero at
is not the location of sign change because it has multiplicity
.
Test intervals are
and
.
Subustiute the values in the inequality
.
If
then
.
If
then
.
If
then
.
The solutions of
are
values such that
is positive.
From the sign chart the solution is
.
From the sign chart,the solution set is
.
The solution set of
is
.
\
\
\