The inequality is
.
is non negative.
Consider
.
is in the form of
.
.
Therefore
.


Let
.
The zeros of
are at
and
.
The zeros of
are at
and
.
Draw a sign chart by using the values
and
.

Note: The solid circle denote that the value are included in the solution set. \ \
\Observe the sign chart:
\The set of value of
denoted in blue color represents the solution set.
Because the zeros at
and
has multiplicity
there is no location of sign change.
The solutions of
are
values such that
is positive or equal to
.
From the sign chart the solution is set of all real numbers.
\From the sign chart, the solution set is
.
The solution set of
is
.