The inequality is .

Let .

Consider the numerator .

The zeros of ocurrs when the numerator is equal to .

.

Therefore has zeros at ..

Consider the denominator .

The undefined point occurs when the denominator is equal to .

Therefore is undefined at ..

Therefore has zeros at and undefined at .

Create a sign chart using the values and .

Note : The solid circle denote that the value are included in the solution set.           

Observe the sign chart :

The set of value of denoted in blue color represents the solution set.

Determine whether is positive or negative on the test intervals.

Test intervals are and .

Subustiute the values in the inequality .

If then .

If then .

If then .

The solutions of are values for which is positive or

equal to .

From the sign chart the solution set is .

is not part of the solution set because the original inequality is undefined at .

The expression is undefined at but it is positive everywhere that it is defined.

Therefore the solution set is .

The Solution set of is  .

Therefore both ajay and mae are wrong.