The function is $\"\"$ .

Continuity Test condition 1:

Find if $\"\"$ exists.

Substitute $\"\"$ in $\"\"$ .

$\"\"$

$\"\"$ .

The function is defined at $\"\"$ .

Continuity Test condition 2:

Find if $\"\"$ exists.

Construct a table that shows the values of $\"\"$ for $\"\"$ -values approaching $\"\"$ from

the left and from the right.

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$
$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$	$\"\"$

Observe the table:

As $\"\"$ tends to $\"\"$ from the left $\"\"$ approaches to $\"\"$ .

As $\"\"$ tends to $\"\"$ from the right, $\"\"$ approaches to $\"\"$ .

$\"\"$ and $\"\"$ .

Since $\"\"$ , $\"\"$ is discontinuous at $\"\"$ .

$\"\"$ does not exist at $\"\"$ .

Continuity Test condition 3:

Check $\"\"$ .

Observe above two conditions,

$\"\"$ does not exist and $\"\"$ is defined.

Because $\"\"$ and $\"\"$ , $\"\"$ has a jump discontinuity at $\"\"$ .

$\"\"$ has a jump discontinuity at $\"\"$ .