The equation is
.
Since the
-term is squared, the parabola is vertical.
Standard form of the vertical parabola is
.
Where
\Vertex :
,
Focus :
,
Axis of symmetry :
,
Directrix :
.
The parabola equation
.
Write the equation in standard form.
\
To change the expression(
) into a perfect square trinomial add
to each side of the equation.
Here
coefficient
.
So,
.
Add
to each side of
.

Compare the above eqation with
.
Since
, the parabola opens up.
Vertex :
,
Focus :
,
Axis of symmetry :
,
Directrix :
.
Graph the vertx, focus, axis of symmetry and directrix.
\Construct a table values to graph the general shape of the curve.
\The equation is
.
Solve for
.

![]() | \
\
| \
![]() | \
![]() | \
\
| \
\
| \
![]() | \
\
| \
\
| \
Graph :
\Graph the vertex, focus, axis of symmetry and directrix of the parabola.
\Plot the points obtained in the above table.
\Connect those points with a smooth curve.
\Graph of
is

Vertex :
.
Focus :
.
Axis of symmetry :
.
Directrix :
.
Graph of
is
