The inequality is
.
Factor the related equation
.



.
Now, there are two ways this product could be less than zero. One factor must be negative and one must be positive.
\Case 1: 

There are NO values for which this situation is true.
\ Case 2: 

Note that the original inequality contains a
symbol. This means that the solution set contain the endpoints of the intervals.
Solution set of the inequality is
.
The solution set in the interval notation is
.
Observe the graph the closed circle means
and
are include in the solution set.
Set notation:
.
Interval notation:
.