The inequality is .

Factor the related equation .

.

.

Now, there are two ways this product could be less than zero. One factor must be negative and one must be positive.

Case 1:

The only condition that makes both true is .

Case 2:

The only condition that makes both true is .

 Solution set of the inequality is .

The solution set in the interval notation is .

Observe the graph the open circle means and are not include in the solution set.

Set notation: .

Interval notation: .