(a)
\The polar equation is
.
where
is measured in tens of thousands of miles.
Construct a table and calculate the values of
on
.
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
Graph:
\1. Draw a polar coordinate plane.
\2. Use the points and polar axis symmetry to sketch the curve.
\.gif\")
(b)
\Observe the graph:
\The minimum distance the satellite will be from the earth occurs at
.
Substitute
in
.

Hence at
,
tens of thousand miles.

Therefore the minimum distance is
miles.
The maximum distance the satellite will be from earth occurs at
.
Substitute
in
.

Hence at
,
tens of thousand miles.

Therefore the maximum distance is
miles.
(c)
\The second satellite rectangular coordinates are
.
Find polar coordinates
.
Find
:
.
Substitute
in the above equation.

Find
:

Since
, the angle is
.
Substitute
in the above equation.

The second satellite passes through the point with polar coordinates
.
Find the location of first satellite, Substitute
in
.


Hence
for first satellite and
for second satellite.
So the two satellites are
tens of thousand miles apart.
Therefore, the two satellites are
miles apart, hence do not collide.
(a)
\Graph the polar equtaion
.
.gif\")
(b) The maximum distance is
miles and the minimum distance is
miles.
(c) The two satellites are
miles apart and they do not collide.