The cubic function is
.
Consider
.
The function is having horizontal tangents at points
and
.
The point
passes through the curve.
Substitute
in
.
The point
passes through the curve.
Substitute
in
.

If the curve
has horizontal tangent at
, then slope of the tangent line is zero.
.
The curve
has horizontal tangent at
.
Therefore,
.

Substitute
in above expression then equate
.

The curve
has horizontal tangent at
.
Therefore,
.

Substitute
in above expression then equate
.

Solve
and
to get
and
values.
Subtract the equation
from
.

Add equations (1) and (2).
\
Substitute
in above expression.

Substitute
in equation
.

Substitute
,
and
in equation
.

Substitute
in
.

Substitute
and
in cubic function
.
\
.