Ship A is 100 km west of ship B.
\Ship A is sailing south at 35 km/h and ship B is sailing north at 25 km/h.
\Find the fast is the distance between the ships changing at time 4:00 PM.
\At any time
,
Consider the distance traveled by the ship A as
.
Consider the vertical distance traveled by the ship B as
.
Consider the distance between the ships is
.
Diagram of the situation at any time
:

From the above figure,
\Apply Pythagorean theorem to the above diagram.
\
.
Differentiate on each side with respect to
.

Ship A is sailing east at 35 km/h.
\Therefore,
km/h.
Ship B is sailing north at 25 km/h.
\Therefore,
km/h.
Rate at which distance between two ships changing at any time
is
.
Find the distance traveled by ship A in 4 hours is
.
Distance = speed
time.

Find the distance traveled by ship B in 4 hours is
.

Find the distance between the ships at 4.00 PM.
\
.
Substitute
and
in above expression.

Consider the result in (1)
.
Substitute corresponding values in above expression.
\

Rate at which distance between two ships changing at 4:00 Pm is
km/h.
Rate at which distance between two ships changing at 4:00 Pm is
km/h.