\
The function
.
Find the horizontal asymptote.
\
Therefore the horizontal asymptote is at
.
Find the vertical asymptote.
\To find the vertical asymptote, equate denominator of the function to zero.
\So
.
Therefore the vertical asymptote is at
.
\
The function is
.
Apply derivative on each side with respect to
.

Find the critical points.
\Here
is never zero, but it is undefined at
.
The critical point is
.
The test intervals are
and
.
| Interval | \Test Value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
\
| \
Decreasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
The function is decreasing on the interval
.
So there is neither local maximum nor local minimum, since the function is decreasing on
.
\
Concavity :
\
.
Again apply derivative on each side with respect to
.

is never zero, but it is undefined at
.
There is no inflection points.
\Consider the test interval are
and
.
| \
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
Down | \
![]() | \
![]() | \
\
| \
\
Up \ | \
The graph is concave up on the interval
.
The graph is concave down on the interval
.
\
Graph :
\Graph the function
:

\
The horizontal asymptote is
.
The function is decreasing on
.
The graph is concave up on
and concave down on
.
Graph of the function
is
.