\
The function is
.
(A)
\Domain :
\The function is
.
All possible values of
is the domain of the function.
Denominator of the function should not be zero
\
and
.
The domain of the function
is
.
\
(B)
\Intercepts :
\To find the
-intercepts, substitute
in the function.

Therefore the
-intercept is
.
To find the
-intercepts, substitute
in the function.

Since at
, the functionis not defined
.
Therefore the
-intercepts is
.
\
(C)
\Symmetry :
\Substitute
in the function.

Here 
Therefore the function
is neither odd nor even.
\
(D)
\Asymptotes :
\Horizontal asymptote :
\
Therefore the horizontal asymptote is
.
Vertical asymptote :
\Vertical asymptote appears when the function is not defined.
\
Since at
, the functionis not defined.

Therefore the vertical asymptote is
.
\
(E)
\Intervals of increase or decrease :
\The function is
.
Differentiate
on each side with respect to
.

is never zero and the function is positive for the domain of
.
Therefore
is increasing over its domain.
\
(F)
\Local Maximum and Minimum values :
\From (E) it is clear that the function is only increasing.
\Therefore is no local minimum or maximum values.
\\
(G)
\Concavity and point of inflection :
\
.
Differentiate
on each side with respect to
.

Find inflection point.
\
is never zero.
There is no inflection point.
\But at
and
, the function is undefined, so split the intervals into
,
and
.
| \
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
\ | \
Up | \
![]() | \
![]() | \
\
| \
\
\ Up \ | \
![]() | \
![]() | \
\
\ | \
Down | \
The graph is concave up in the interval
,
.
The graph is concave down in the interval
.
\
(H)
\Graph :
\Graph of the function
:

\
(A) The domain of the function
is
.
(B)
-intercept is
and
-intercepts are
.
(C) No symmetry.
\(D) The horizontal asymptote is
and the vertical asymptote is
.
(E) Increasing on
,
and
.
(F) There is neither local minimum nor local maximum.
\(G) Concave up on
and
.
concave down on
.
(H) Graph of the function
is
.