$\"\"$

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The points are $\"\"$ , $\"\"$ and $\"\"$ .

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Find the line equation using the two points $\"\"$ and $\"\"$ .

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Point-slope form of line equation: $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in above formula.

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$\"\"$

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$\"\"$ .

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Find the line equation using the two points $\"\"$ and $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in point-slope formula.

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$\"\"$

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$\"\"$ .

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Find the line equation using the two points $\"\"$ and $\"\"$ .

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Substitute $\"\"$ and $\"\"$ in point-slope formula.

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$ .

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$\"\"$

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Graph:

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Form the triangle by above line equations.

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Graph the lines $\"\"$ , $\"\"$ and $\"\"$ .

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Shade the required region.

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$\"\"$

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Observe the graph :

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Region enclosed by the given curves is in between $\"\"$ and $\"\"$ .

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$\"\"$

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Area enclosed by the curves $\"\"$ and $\"\"$ between $\"\"$ and $\"\"$ is

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$\"\"$ .

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Observe the graph:

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In the interval $\"\"$ , upper curve is $\"\"$ and the lower curve is $\"\"$ .

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In the interval $\"\"$ , upper curve is $\"\"$ and the lower curve is $\"\"$ .

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Area of the region :

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$\"\"$ .

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$

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$\"\"$ .

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Area of the region is $\"\"$ sq-units.

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$\"\"$

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Area of the region is $\"\"$ sq-units.