The function is
and the interval is
.
(a)
\Average value of the function
on
is defined as
.
Here
.
Average value of
is
.
Average value of the function
on
is
.
(b)
\Find
such that
.
Consider
.

We have
.
Substitute
and
in
.
.
Since it is very difficult to find the roots by solving the trigonometric equation, use the graph to find
value.
Graph:
\Graph the functions
and
.
.gif\")
From the graph,
\It is observed that, intersection points are
and
.
The values of
are
-coordinates of the points.
and
.
(c)
\Graph the function
and rectangle under the interval
.

(a)
\Average value of the function
on
is
.
(b) The values of
are
and
.
(c) Graph:
\
.