$\"\"$

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(a)

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Inverse function definition:

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If $\"\"$ be a one-to-one function with domain $\"\"$ and range $\"\"$ , then its inverse function $\"\"$ has domian $\"\"$ and range $\"\"$ and $\"\"$ is defined by $\"\"$ , for any $\"\"$ in $\"\"$ .

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Domain of $\"\"$ is range of $\"\"$ .

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Range of $\"\"$ is domain of $\"\"$ .

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Domain of $\"\"$ is $\"\"$ and range of $\"\"$ is $\"\"$ .

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$\"\"$

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(b)

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Let the function is given by the formula $\"\"$ .

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Solve above equation for $\"\"$ in terms of $\"\"$ .

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To express the inverse function $\"\"$ interms of $\"\"$ ,interchange $\"\"$ and $\"\"$ then the resulting equation is $\"\"$ .

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$\"\"$

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(c)

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To find the graph of $\"\"$ , first verify $\"\"$ is a one-to-one by horizontal line test.

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The graph of $\"\"$ is obtained by reflecting the graph of about the line $\"\"$ .

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$\"\"$

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(a) Domain of $\"\"$ is $\"\"$ and range of $\"\"$ is $\"\"$ .

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(b) Solve above equation for $\"\"$ in terms of $\"\"$ and to express the inverse function $\"\"$ interms of $\"\"$ ,

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interchange $\"\"$ and $\"\"$ then the resulting equation is $\"\"$ .

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(c) The graph of $\"\"$ is obtained by reflecting the graph of about the line $\"\"$ .