The function is
,
.
Apply derivative on each side with respect to
.

Find the critical numbers of
, by equating
to zero.

.
Since
then test intervals are
and
.
| Interval | \![]() | \
Sign | \
![]() | \
\
| \
Decreasing | \
![]() | \
\
| \
Increasing | \
Therefore
is decreasing on
and increasing on
.
As
changes its sign from positive to negative,
has an absolute minimum at
.
Substitute
in
.

Absolute minimum of the function is
.
Absolute minimum of the function is
.