(a).

The size of poulation growth after  years is .

Observe the table :

Consider initial year is  and population is  .

The time between every two consecutive years is  years.

Then consider year , hence .

The population growth equation is .

Substitute ,  and  in the equation .

The population growth equation is .

The population growth equation is .

Find the population for the year .

For the year , then .

Substitute  in the equation .

 million.

The population for the year  is  million.

Find the population for the year .

For the year , then .

Substitute in the equation

 million.

The population for the year  is  million.

According to the table, the population for the year  is  million.

Hence the equation is not appropiate as the difference is to high.

(b).

Observe  the table.

Consider initial year was  and  the population is .

The time between every two consecutive years is  years.

Then consider year  , hence .

The population growth equation is  .

Substitute ,   and  in the equation .

The population growth equation is .

Observe the table year  was .

Substitute  in the equation   

 million.

According to the table, the population for the year  is  million.

Hence the prediction is appropiate as the difference is low.

(c).

Observe  the table ,consider initial year was  and  .

The time between every two years is  years.

Then consider year   ,hence .

The population growth equation is .

Substitute  and   and in the equation 

The population growth equation is .

Observe the table year  was .

Substitute in the equation   .

 million

According to the table, the population for the year  is  million.

Hence the prediction is appropiate as the difference is low.

(a). million and  million.

(b). million.

(c). million.