A cardiac monitor is used to measure the heart rate of a patient after surgery.
\The number of patients heartbeats are taken in the table for different values of time
.
Find the slope of the secant lines between the points using the table of values.
\(a)
\Find the slope at
and
.
At
and the corresponding patient heartbeat is
.
At
and the corresponding the patient heartbeat is
.
So the obtained points are
and
.
Slope of the two points is
.
The slope of the secant line is
heartbeats/min.
(b)
\Find the slope at
and
.
At
and the corresponding patient heartbeat is
.
At
and the corresponding the patient heartbeat is
.
So the obtained points are
and
.
Slope of the two points is
.
The slope of the secant line is
heartbeats/min.
(c)
\Find the slope at
and
.
At
and the corresponding patient heartbeat is
.
At
and the corresponding the patient heartbeat is
.
So the obtained points are
and
.
Slope of the two points is
.
The slope of the secant line is
heartbeats/min.
(d)
\Find the slope at
and
.
At
and the corresponding patient heartbeat is
.
At
and the corresponding the patient heartbeat is
.
So the obtained points are
and
.
Slope of the two points is
.
The slope of the secant line is
heartbeats/min.
Conclusion :
\After
minutes the patients heart rate decreases.
Find the patient heart rate after
minutes.
Use the average of the slopes of the patients heart rate after
minutes.
So consider the points near to
are
and
.
The slope of the heart rate at
and
is
heartbeats/min.
The slope of the heart rate at
and
is
heartbeats/min.
The average of the slopes is
heartbeats/min.
The patient heart rate after
minutes is
heartbeats/min.
(a)
heartbeats/min.
(b)
heartbeats/min.
(c)
heartbeats/min.
(d)
heartbeats/min.
The patient heart rate after
minutes is
heartbeats/min.