$\"\"$

\

The equations of linear system are $\"\"$ and the ordered pair is $\"\"$ .

\

To tell the ordered pair $\"\"$ is a solution of linear system, substitute $\"\"$ for x and 0 for y in each of the original equations.

\

Substitute $\"\"$ for x and 0 for y in the equation 1: $\"\"$ .

\

$\"\"$

\

$\"\"$ .

\

Substitute $\"\"$ for x and 0 for y in the equation 2: $\"\"$ .

\

$\"\"$

\

$\"\"$

\

$\"\"$ .

\

The above statement is not true, so $\"\"$ is not a solution of equation 2.

\

\ \ Because $\"\"$ is not a solution of equation 2, it is not a solution of the linear system. $\"\"$

\

The ordered pair is $\"\"$ .

\

To tell the ordered pair $\"\"$ is a solution of linear system, substitute 0 for x and $\"\"$ $\"\"$ for y in each of the original equations.

\

Substitute 0 for x and $\"\"$ $\"\"$ for y in the equation 1: $\"\"$ .

\

$\"\"$

\

$\"\"$ .

\

Substitute 0 for x and $\"\"$ $\"\"$ for y in the equation 2: $\"\"$ .

\

$\"\"$

\

$\"\"$

\

$\"\"$ .

\

The above statement is true, so $\"\"$ is a solution of equation 2. \ \ Because $\"\"$ is a solution of each equation, it is a solution of the linear system. $\"\"$

\

The option B is correct answer.