$\"\"$

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The system of equations are $\"\"$ and its solution is $\"\"$ .

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Substitute the values of $\"\"$ in the above linear system.

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Equation 1: $\"\"$ .

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Equation 2: $\"\"$ .

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Neither variable has a common coefficient.The coefficient of the a - variables are 4 and 2 and their least common multiple is 4, so multiply each equation by the value that will make the a - coefficient 4.

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To get two equations that contain opposite terms multiply the second equation by 2.

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Write the equations in column form and add the corresponding columns to eliminate a - variable.

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$\"\"$ . $\"\"$

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The resultant equation is $\"\"$ and solve for b.

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Divide each side by 6.

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$\"\"$

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Cancel common terms.

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$\"\"$ .

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Substitute the value of $\"\"$ in either of the original equations and solve for a.

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The second equation: $\"\"$ .

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$\"\"$

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$\"\"$ $\"\"$

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Subtract 16 from each side.

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$\"\"$

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$\"\"$ .

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Divide each side by negative 2.

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$\"\"$

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Cancel common terms.

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$\"\"$ . $\"\"$

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The solution $\"\"$ .