Algebra 2, 2008
Given function .
The f(x) has degree 3 and three zeros.
x |
1 |
5 |
7 |
51 |
3 |
1 |
2 |
13 |
12 |
1 |
1 |
4 |
11 |
40 |
2 |
1 |
7 |
7 |
37 |
3 |
1 |
8 |
17 |
0 |
Above table one zero at , the depressed polynomial of this zero, is quadratic.
The quadratic equation is .
The function has one real zero at and two imaginary roots,
.
The solution is , two imaginary roots .
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