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25

Step-by-step Answer
PAGE: 367SET: ExercisesPROBLEM: 25
Please look in your text book for this problem Statement

Given function  .

The f(x) has degree 3 and three zeros.

 

x

   1

5

7

51

  3

   1

  2

13

12

  1

   1

4

11

40

2

   1

7

   7

37

3

   1

8

  17

0

Above table one zero at , the depressed polynomial of this zero, is quadratic.

The quadratic equation is .

Syntax error.

Syntax error.

x equal fraction numerator 8 plus-minus square root of 64 minus 68 end root over denominator 2 end fraction

x equal fraction numerator 8 plus-minus square root of minus 4 end root over denominator 2 end fraction

x equal fraction numerator 8 plus-minus 2 straight i over denominator 2 end fraction

x equal 4 plus-minus straight i

The function has one real zero at and two imaginary roots,

x equal 4 plus straight i space italic and space straight x equal 4 minus straight i.

The solution is , two imaginary roots x equal 4 plus straight i space italic and space straight x equal 4 minus straight i.



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