First find the *y*-intercept value by substituing the slope and coordinates of the

given point in the equation.

*y* = *mx* + *b* (Slope-intercept form line equation)

1 = 3 + *b* (Substitute 3 for *m*, 1 for *x*, and 1 for *y*)

1 – 3 = 3 + *b* – 3 (Subtract 3 from each side)

1 – 3 = 3 – 3 + *b *(Apply Commutative property of addition: *a + b = b + a*)

1 – 3 = *b ** *(Apply additive inverse property: 3 – 3 = 0)

*b* = – 2 (Subtract: 1 – 3 = –2)

Now substitute *m *=* *3 and *b* = – 2 slope-intercept form line equation.

*y* = 3*x* + (– 2)

*y* = 3*x* – 2 (Simplify)

The equation of the line that passes through the point (1, 1) and has a slope of 3 is

*y* = 3*x* – 2.

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