Step-by-step Answer
PAGE: 39SET: ExercisesPROBLEM: 47
Please look in your text book for this problem Statement

The circle equation is .

Rewrite the equation as .

Compare it with circle equation .


Diameter of circle .

Let the side of square be .

In this case the squares diagonal is diameter of the circle.

The diagonals of a square bisects each other and the diagonals split the square into two right angle triangles.

Diameter of circle is hypotenuse of the triangles.

From the Pythagorean theorem .


 Area of the square .

Substitute in .


Area of the square is square units.


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