Pre-Calculus, 9th edition
31

 PAGE: 672 SET: Exercises PROBLEM: 31

The equation is .

From problem number (21): , and .

Substitute and in .

The rotational equation is .

The rotational equation is .

The general form of hyperbola is .

Where the hyperbola is transverse about -axis and   is the center.

is the distance between center and vertex.

is the distance between center and focus and .

The vertices of the hyperbola is .

Compare the equation with standard form.

Center is origin.

Transverse axis is the -axis.

Vertices at .

Graph:

Graph the equation .

.

.

The rotational equation is .

The equation represents Hyperbola.

Transverse axis is the -axis.

Vertices are at .

Graph of the equation .

.

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