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dentify the outlier in the data set. Then find the mean, median, mode(s), range and standard deviation when the outlier is included and when it is not.
15,18,20,26,18,62
asked Apr 22, 2014 in ALGEBRA 2 by anonymous

1 Answer

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15 ,18, 20 , 26, 18 , 62.

Mean : -

Mean is the ratio between sum of the total numbers and total given numbers

Mean = ( 15 +18+ 20+26+ 18+ 62) / 6.

Mean=159/6

Mean=26.5

Median :-

15 ,18, 20 , 26, 18 , 62.

To find the median , we must need to put the numbers in order from smallest to largest.

15 ,18, 18, 20 , 26, 62.

Median is the arithmetic mean of two middle most numbers = (18+20)/2 = 38/2 =19

So the median is 19.

Mode :-

The mode is  the value which occures most often in a data.

15 ,18, 20 , 26, 18 , 62.

This is the  most common value 18.

So we say 18 is the mode.

Range : -

The range is the different between the largest and smallest value in data  in this case 62 and15

So the range is 62 - 15  = 47.

Standard deviation : -

15 ,18, 20 , 26, 18 , 62.

 Mean = 26.5

To caliculate the numbers  deviation  first  compute difference of each data point

from the mean ,and sqare the result of each.

(15 - 26.55)^2 = (-11.5)^2 = 132.25

(18 - 26.5)^2  = (-8.5)^2 = 72.25

(20 - 26.5)^2 =(-6.5)^2 = 42.25

(26 - 26.5)^2 =(0.5)^2 = 0.25

(18 - 26.5)^2 = (-8.5)^2 = 72.25

(62 - 26.5)^2 = (35.5)^2 = 1260.25

Next ,compute the mean of these values and take the square root.

= (132.5 + 72.25 + 42.25+ 0.25 + 72.25 + 1260.25)/6

= (1579.75) / 6

= 263.29

Sqrt(263.29) = 16.2262

standard deviation of given numbers is 16.23.

Solution : Mean =26.5, Median= 19, mode =18, Range =47 , Standard deviation=16.23.

answered Apr 22, 2014 by friend Mentor

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