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In an arithmetic progression, the sum of the first half of the terms is 54,

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the sum of the second half is 108 and the sum of the first?

 

1.) in an arithmetic progression, the sum of the first half of the terms is 54, the sum of the second half is 108 and the sum of the first and last term is 54. Find the number of terms.
2.) the first and the last term of a geometric progression is equal to -8 and 1 respectively. If the sum of all the terms is -5, find the number of terms.
asked Apr 24, 2014 in ALGEBRA 2 by anonymous

2 Answers

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Note :

The sum Sn of the first n terms of an arithmetic series is given by image, where a1 = first term, an = last term.

The sum Sn of the first n terms of geometric series is given by  image, where a = first term, r = common ratio.

1).

Sum of the first half of the terms image.

Sum of the second half of the terms image.

Sum of the first term and last term image.

Total sum = Sum of the first half of the terms + Sum of the first half of the terms.

image

image

image

image

image.

The number of terms in the given arithmetic progression is 6.

answered Apr 28, 2014 by lilly Expert
0 votes

2).

First term of the geometric progression (a ) = - 8.

Last term of the geometric progressin  image.

Substitute a = - 8 in image.

image.

Sum of geometric progression image.

Substitute a = - 8 and image in image.

image

image

image

image

image.

To find n, substitute the value r = - 1 / 2 in image.

image

image

 

n = 4.

The number of terms of the geometric progression is 4.

answered Apr 28, 2014 by lilly Expert

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