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H(t) = t^2 + 4t; t = −1, t = 4, need help with average rate of change problem?

+1 vote

A function is given. Determine the average rate of change of the function between the given values of the variable.
h(t) = t^2 + 4t; t = −1, t = 4

asked Feb 8, 2013 in CALCULUS by rockstar Apprentice

1 Answer

0 votes

h(t) = t2 + 4t; t = −1, t = 4

If t = -1 ⇒ h(-1)=(-1)2+4(-1)⇒h(-1)=1-4 = -3

If t = 4 ⇒ h(4)=(4)2+4(4) = 16+16=32

The average rate of change of the function is [h(4)-h(-1)]/[4 - (-1)]

= [32 - (-3)] / [4 + 1]

= (32+3)/(5)

= 35/5 = 7.

answered Feb 8, 2013 by britally Apprentice

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