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Need help with pre-calculus question?

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asked May 10, 2014 in CALCULUS by anonymous

1 Answer

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Given : x = (1/2)t and y = 3t^3 - 1.

Solve x = (1/2)t for t.

t  = 2x.

To eliminate the parameter t, substitute t = 2x in  y = 3t^3 - 1.

y = 3(2x)^3 - 1

y = 3(8x^3) - 1

y = 24x^3 - 1.

answered May 10, 2014 by lilly Expert

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