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Write an equation for the line containing this points (0,6) and (-2,10)

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asked May 15, 2014 in ALGEBRA 1 by marleney Novice

1 Answer

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The point - slope from of line equation is y - y1 = m(x - x1), m is slope and (x1, y1) is point.

The points are (x1, y1) = (0, 6) and (x2, y2) = (-2, 10).

Slope m = (y2 - y1)/(x2 - x1) = (10 - 6) / (-2 - 0) = 4 / -2 = -2.

To write the line equation, we can use either of the two given points.

Consider the point (x1, y1) = (0, 6).

Substitute m = -2 and (x1, y1) = (0, 6) in point-slope form equation or y - y1 = m(x - x1).

y - 6 = -2 ( x - (0) )

y - 6 = -2 ( x )

2x + y - 6 = 0.

The equation for the line containing the points (0,6) and (-2,10) is 2x + y - 6 = 0.

answered May 15, 2014 by joly Scholar

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