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Find all rational zeros of h(x)= 3x^3+7x^2+8x+2.

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Factor completely?

asked Jul 14, 2014 in ALGEBRA 2 by anonymous

1 Answer

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Identify Rational Zeros  

Usually it is not practical to test all possible zeros of a polynomial function using only synthetic substitution. The Rational Zero Theorem can be used for finding the some possible zeros to test.

The function h (x ) = 3x3+ 7x2+ 8x + 2

If p /q is a rational zero, then p  is a factor of 2 and is a factor of 3.

The possible values of p  are   ± 1,  and   ± 2.

The possible values for q  are ± 1 and ± 3.

So, p /q = ± 1, ± 1/3, ± 2 and ± 2/3.

Make a table for the synthetic division and test possible  zeros.

p /q 3 7 8 2
1 3 10 18 20
-1 3 4 4 -2
1/3 3 8 32/3 34
-1/3 3 6 6 0

Since h (-1/3)   =   0,  x  =  -1/3 is a zero. The depressed polynomial is   3x2+ 6x + 6 = 0

The above equation can be written as x2 + 2x + 2 = 0

Factoring of h (x ) = 3x3+ 7x2+ 8x + 2  = (x + 1/3)(x2 + 2x + 2)

Since the depressed polynomial of this zero, x2 + 2x + 2, is quadratic, use the Quadratic Formula to find the roots of the related quadratic equation.

Roots are image

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h (x ) = 3x3+ 7x2+ 8x + 2 have two imaginary roots are image.

h (x ) = 3x3+ 7x2+ 8x + 2 have only one rational zero is -1/3.

answered Jul 14, 2014 by david Expert

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