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Help! Trig. Explain !

+1 vote

Simplify

Csc^4x - cot^4x?

asked Feb 21, 2013 in TRIGONOMETRY by angel12 Scholar

1 Answer

+2 votes

csc4x - cot4x

= (csc2x)2 - (cot2x)2

Mathematical formula: (a2 - b2) = (a + b)(a - b)

= (csc2x + cot2x)(csc2x - cot2x)

Pythagorean Identities: csc2θ - cot2θ = 1

= (csc2x + cot2x)(1)

Reciprocal identities: cscθ =1/sinθ and Quotient Identities: cotθ =cosθ/sinθ.

= 1/sin2x + cos2x/sin2x

Rewrite the expression with common denominator.

= [1 + cos2x] / sin2x.

answered Feb 21, 2013 by richardson Scholar

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