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Given that P = (-5, 11) and Q = (-6, 4), find the component form and magnitude of vector QP.

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asked Aug 4, 2014 in CALCULUS by Tdog79 Pupil

1 Answer

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P = (- 5, 11) and Q = (- 6, 4).

The vector QP is equivalent to the  directed line segment " P - Q " = < 1, 7 >.

When, we write < >, we mean that The vector has initial at the origin and terminal point at (1, 7).

This notation is called the component form of the vector.

The length of the vector is called the magnitude.

Magnitude = ||<x, y>|| = √(x2 + y2).

Magnitude of vector QP = (12 + 72) = √(1 + 49) = 50.

answered Aug 4, 2014 by lilly Expert

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