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Finding Trig Identities~ Need asap

+1 vote

I am in need of some help solving this Trig Identity:

cotx/csc+1=cscx-1/cotx

asked Feb 26, 2013 in CALCULUS by johnkelly Apprentice

1 Answer

+1 vote

cotx/cscx+1

Multiply denominater and numerator with cscx-1

=cotx(cscx-1)/(cscx+1)(cscx-1)

Simplify

=cotx(cscx-1)/(csc^2x-1)

Recall  csc2 θ - cot2 θ = 1 ---->  csc2 θ-1 = cot2θ

=cotx(cscx-1)/(cot^2x)

=cscx-1/cotx

hope that helps you

answered Mar 1, 2013 by bradely Mentor

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