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While dragging a crate a workman exerts a force of 628 N. Later, the mass of the crate is increased by a factor of 3.8. If the workman exerts the same force, how does the new acceleration compare to the old acceleration?

asked Mar 8, 2013 in PHYSICS by anonymous Apprentice

1 Answer

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Exerted force,F=628 N

Initial mass,m1=m

Final mass,m2=m+3.8 m=4.8 m

Same force in both cases

F1=F2

m1a1=m2a2

ma1=4.8 m*a2

a1=4.8a2

a2=0.208 a1

 

                         

answered Mar 8, 2013 by bradely Mentor

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