Welcome :: Homework Help and Answers :: Mathskey.com

Recent Visits

  
Welcome to Mathskey.com Question & Answers Community. Ask any math/science homework question and receive answers from other members of the community.

13,435 questions

17,804 answers

1,438 comments

774,880 users

how to solve

0 votes
5.3 The plungers of a three -cylinder pump have diameters of 12 cm and a stroke length of 50 cm. The pressure during the delivery stroke is 1 000 kPa. Calculate the following: 5.3.1 The power required to drive the pump at 350 r/min if the efficiency of the motor is 90% 5.3.2 The volume of the water delivered per minute in l/min if there is a slip of 13%
asked Oct 27, 2014 in PHYSICS by anonymous

2 Answers

0 votes

(5.3.2)

Consider Single - acting pump

Number of Cylinders n = 3

Piston diameter d = 12 cm

d = 12/100 m = 0.12 m

Stroke length s = 50 m

s = 50/100 = 0.5 m

Slip = 13% = 0.13

Speed N = 350 RPM

Cross sectional area of piston A = (¼)πd2

A = (¼)π(0.12)2

A = 0.0113 m2

Volume of Water discharge Q = (A×s×n×N)/231

Q = (0.0113×0.5×3×350)/231

Q = 0.0257 Gallons per minute

But due to slip 13% is lost.So

Q = 0.0257× 0.13 Gallons per minute

Q = 0.003341 Gallons per minute

1 Gallons per minute = 3.78541 litres/minute.

Q = 3.78541×0.003341

Q = 0.01264 litres/minute.

The volume of water delivered is 0.01264 litres/minute.

answered Oct 29, 2014 by lilly Expert
0 votes

(5.3.1)

Consider Single - acting pump

Number of Cylinders n = 3

Piston diameter d = 12 cm

d = 12/100 m = 0.12 m

Stroke length s = 50 m

s = 50/100 = 0.5 m

Slip = 13% = 0.13

Speed N = 350 RPM

Prassure P = 1000 kPa = 1 MPa

1 MPa = 145.0377 psi

P = 145.0377 Psi

Efficiency η = 90 % = 0.9

Cross sectional area of piston A = (¼)πd2

A = (¼)π(0.12)2

A = 0.0113 m2

Volume of Water discharge Q = (A×s×n×N)/231

Q = (0.0113×0.5×3×350)/231

Q = 0.0257 Gallons per minute

Fluid Hourse Power FHP = (P x Q) / (1714 x η)

P = Pressure in psi ( per square inch )

Q = Flowrate in GPM ( Gallons per minute )

FHP = (145.0377 x 0.0257) / (1714 x 0.9)

FHP = 0.0024 HP

1 Hp = 745.699872 Watts

Power = 0.0024 x 745.699872

Power = 1.7896 Watts

The power required to drive the pump is 1.7896 Watts.

 

answered Oct 29, 2014 by lilly Expert

Related questions

asked Oct 28, 2014 in PHYSICS by anonymous
asked Nov 20, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 27, 2014 in PHYSICS by anonymous
asked Oct 27, 2014 in PHYSICS by anonymous
asked Jul 21, 2014 in PHYSICS by anonymous
asked Jan 26, 2016 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
asked Oct 28, 2014 in PHYSICS by anonymous
...