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1- What is the charge to mass ratio of a particle travelling (4.80x10^5) m/s  that is deflected in an arc or radius (8.000x10^-2) m as it travels through a magnetic field of (6.000x10^-1) T?

2- Some positively charged particles are found to pass un-deflected through perpendicular magnetic and electric fields. The magnetic field strength is 0.650 T and the electric field strength is 2.10 x 105 N/C. The speed of the particles is____ x 105m/s. 

asked Dec 4, 2014 in PHYSICS by anonymous

2 Answers

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1)

Particle velocity v = 4.8 × 105 m/s

Arc radius r = 8 × 10-2  m

Magnetic field strength B = 6 × 10-1  T

The charge to mass ratio (Q/m) = v/rB

(Q/m) = v/rB

= (4.8 × 105  ) / ( 8 × 10-2 )( 6 × 10-1 )

= (4.8/48) × 105+3

= 0.1 × 108

= 1 × 107  C/kg

The charge to mass ratio of particle is 1 × 107  C/kg.

answered Dec 4, 2014 by Shalom Scholar
0 votes

2)

The magnetic field strength B = 0.65 T

The electric field strength E = 2.1 x 105 N/C

Speed of the particles v = E / B

v = (2.1 x 105) / 0.65

v = (2.1 x 105) / 0.65

v = 3.231 x 105 m/s

Speed of the particles is 3.231 x 105 m/s.

answered Dec 4, 2014 by Shalom Scholar

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