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SUPER AWESOME MATH PROBLEM

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Derivative of e^-(1/1+x)?

asked Apr 17, 2013 in CALCULUS by homeworkhelp Mentor

3 Answers

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Apply derivative with respective  x to each side for above function

The derivative of 1 / (1+ x) = -1 / (1 + x)2 and derivative of ex = ex.

d / dx (e-1/(1 + x))         = e-1/(1 + x) × 1 / (1+ x)2 ×(o + 1)

                                 = e-1/(1 + x) × 1 / (1+ x)2

                                 =[e-1/(1 + x) ] / (1+ x)2 .

 

 

 

answered Apr 18, 2013 by diane Scholar
0 votes

 

Possible derivation:

d/dx(e(-(x+1 1/1)))

Rewrite the expression: e-(x+1 1/1)= e(-x-1)

d/dx(e(-x-1))

Using the chain rule, d/dx(e(-x-1)))= eu( du)/( dx), where u = -x-1 and  d/du(eu) = eu:

e(-x-1) (d/dx(-x-1))

Differentiate the sum term by term and factor out constants:

e(-x-1) (d/dx(-1)-d/dx(x))

The derivative of -1 is zero:

e(-x-1) (0-d/dx(x))

Simplify the expression:

e(-x-1) (d/dx(x)))

The derivative of x is 1:

Answer: e(-x-1)

answered Apr 22, 2013 by Naren Answers Apprentice
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i hope it helps a lil

answered Apr 22, 2013 by Naren Answers Apprentice

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