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Some math genius please help me!?

0 votes

I'm having a problem with these two:

Given:
f(x) = (3/x^2)-5
g(x) = sqrt(2x+7)

Let p(x) = f(g(x)) and q(x) = g(f(x))

1. Whats p(x) = ?
2. Whats q(x) = ?

asked Apr 20, 2013 in ALGEBRA 1 by futai Scholar

2 Answers

0 votes

1.

f(x) = (3 / x2) - 5

g(x) = (2x + 7)

p(x) = f(g(x))

Substitute g(x) = (2x + 7) in the p(x)

p(x) = f((2x + 7) = f(t) = (3 / t2 - 5)

Therefore p(x) = (3 / 2x + 7) - 5

p(x) = (3 - 10x - 35) / 2x + 7

p(x) = -(10x + 32) / 2x + 7.

answered Apr 20, 2013 by diane Scholar
edited Apr 20, 2013 by diane
0 votes

2.

f(x) = (3 / x2) - 5

g(x) = √(2x + 7)

q(x) = g(f(x))

Substitute f(x) = (3 / x2) - 5 in the q(x)

q(x) = g((3 / x2) - 5)) = g(t) = √2t + 7

Therefore q(x) = (√2((3 / x2) - 5) + 7).

answered Apr 20, 2013 by diane Scholar

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