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Answer question and show work please?

0 votes
solve the equation foe the interval [0, 2pie]

csc^5x - 4cscx = 0
asked Apr 22, 2013 in ALGEBRA 1 by abstain12 Apprentice

1 Answer

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csc5x - 4cscx = 0 [0, 2pi]

Take out common term cscx

cscx(csc4x - 4) = 0

cscx = 0 or csc4x - 4 = 0

sinx = ∞ This is wrong

Therefore csc4x = 4

Take fourth root  to each side

cscx = ±√2 at  [0 , 2pi]

sinx = ±(1 / √2)  at [0 , 2pi]

x = pi / 4 , 3pi / 4 , 5pi / 4 , 7pi / 4.

answered Apr 22, 2013 by diane Scholar

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